Day by Date

• Problem Description

  
  "Computation of the date either previous or forthcoming dates is quiet easy. But it is quiet difficult to calculate the day from a particular given date. You are required to find a day from a particular date given to you.
  Input
  It consists of a single line entry consisting of date in format dd mm yyyy. i.e. the input line consists of the three numbers written in order followed by spaces. Eg. Input for 18-12-1990 is be written as 18 12 1990
  Output
  It consists of single line output showing the day for that particular date.
  "

• Test Case 1

  
  Input (stdin)

  14 3 2012
  
  

  Expected Output

  Wednesday

• Test Case 2

  
  Input (stdin)

  25 01 2011
  
  

  Expected Output

  Tuesday

• Program

• #include<stdio.h>
  char * day[] ={"Sunday", "Monday","Tuesday", "Wednesday","Thursday", "Friday", "Saturday"};
  int solve(int y, int m, int d)
  {
         static int t[] = {0, 3, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4};
         y -= m < 3;
         return (y + y/4 - y/100 + y/400 + t[m-1] + d) % 7;
  }
  int main()
  {
      int d, m, y;
      scanf("%d%d%d",&d,&m,&y);
      int w = solve(y, m, d);
      printf("%s\n",day[w]);
      return 0;
  }
  

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