Student Management Array of Structure

• Problem Description

  
  1 Create a structure "student".
  
  2. This structure has three members: name (string), roll (integer) and marks (float).
  
  3. Created a structure array of size 3 to store information of 3 students and structure variable as "s".
  
  Hint: s[3];
  
  4. Using for loop, the program takes the information of 3 students from the user and displays it on the screen.
  

• Test Case 1

  
  Input (stdin)

  Bogar 99.33
  
  Siddhar 99.44
  
  Tamil 99.99
  
  

  Expected Output

  Roll number=1
  
  Name=Bogar
  
  Marks=99.33
  
  Roll number=2
  
  Name=Siddhar
  
  Marks=99.44
  
  Roll number=3
  
  Name=Tamil
  
  Marks=99.99

• Test Case 2

  
  Input (stdin)

  Tom 98.22
  
  Bob 65.12
  
  Alice 45.43
  
  

  Expected Output

  Roll number=1
  
  Name=Tom
  
  Marks=98.22
  
  Roll number=2
  
  Name=Bob
  
  Marks=65.12
  
  Roll number=3
  
  Name=Alice
  
  Marks=45.43

• Program

• #include <stdio.h>
  struct student
  {
    char name[10];
    int roll;
    float marks;
  }s[3];
  
  int main()
  {
    int i;
    for(i=0;i<3;i++)
    {
      s[i].roll=i+1;
      scanf("%s",s[i].name);
      scanf("%f",&s[i].marks);
    }
    for(i=0;i<3;i++)
    {
      printf("Roll number=%d\n",i+1);
      printf("Name=%s\n",s[i].name);
      printf("Marks=%.2f\n",s[i].marks);
    }
     return 0;
  }