Lucy

• Problem Description

  
  Lucy is celebrating her 15th birthday. Her father promised her that he will buy her a new computer on her birthday if she solves the question asked by him. He asks Lucy to find whether the year on which she had born is leap year or not. Help her to solve this puzzle so that she celebrates her birthday happily. If her birth year is 2016 and it is a leap year display 2016 is a leap year.? Else display 2016 is not a leap year and check with other leap year conditions.

• Test Case 1

  
  Input (stdin)

  1900
  
  

  Expected Output

  1900 is not a leap year

• Test Case 2

  
  Input (stdin)

  2016
  
  

  Expected Output

  2016 is a leap year

• Program

• #include <stdio.h>
  int main()
  {
    int a;
    scanf("%d",&a);
    if(a%400==0)
    {
      printf("%d is a leap year",a);
    }
    else if(a%100==0)
    {
      printf("%d is not a leap year",a);
    }
    else if(a%4==0)
    {
      printf("%d is a leap year",a);
    }
    else
      printf("%d is not a leap year",a);
    return 0;
  }